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23 July, 06:33

Find the Empirical formula for 0.765g Cr, 0.235g O

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  1. 23 July, 06:58
    0
    CrO

    Explanation:

    0.765g Cr

    0.235g O

    O = 16g/mol

    Cr = 52g/mol

    O 2-

    Cr 2+, 3+, 6+

    0.765 + 0.235 = 1

    so 76.5% Cr

    23.5% O

    76.5/52 = 1.47/1.47 = 1

    23.5/16 = 1.47/1.47 = 1

    CrO
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