How many moles of O2 will be formed from 1.65 moles of KCIO3? (2KClO3->2KCl + 3O2)

2.475 mol of O2 formed.

Explanation:

Given 1.65 moles of KClO3 as the target amount in the reactant, used the coefficient of the balanced chemical reaction involved to determine the number of moles of O2 molecules formed.

x mole of O2 = 1.65 mol KClO3 x [ (3 mol O2) / (2 mol KClO3) ] = 2.475 mol of O2

x mole of O2 formed = 2.475 mol of O2