Calculate the energy to heat the cube of silver, with a volume of 20.0 cm3, from 15 âc to 32 âc. (assume that density of silver is 10.5 g/cm3, specific heat for silver is 0.235 j/gâc.)

Energy = mass * specific heat capacity * change in temperature ...

We ain't given mass in the question but volume and density as well ...

Then we can use the relationship density = mass/volume

Mass = density * volume

Mass = 10.5g/cm³ * 20cm³

Mass = 210g

Energy = 210 * 0.235 * (32-15)

Energy = 210*0.235*17

Energy = 838.95J

Or 0.84Kj ...