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11 March, 15:54

What volume of 0.175 m na3po4 solution is necessary to completely react with 95.4 ml of 0.102 m cucl2?

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  1. 11 March, 16:18
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    The volume of 0.175 M Na3PO4 solution that is necessary to completely react withn 95.4 ml of 0.102 M cuCl2 is

    calculation

    Step 1: write the equation for reaction

    3CuCl2 (aq) + 2Na3Po4 → Cu3 (PO4) 2 + 6 NaCl

    Step 2 : find the moles of CuCl2

    moles = molarity x volume in liters

    volume in liters = 95.4 / 1000 = 0.0954 L

    moles is therefore = 0.0954 L x 0.102 M = 0.00973 moles

    Step : use the mole ratio to calculate the moles of Na3Po4

    The mole ratio of CuCl2 : Na3PO4 is 3:2 therefore = 0.00973 x2/3 = 0.00649 moles

    Step 4 : find the volume of Na3PO4

    volume = moles/molarity

    = 0.00649 mole / 0.175=0.037 M
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