If you weighed out 0.38 g of calcium and reacted it with an excess of hcl, how many moles of h2 (g) would you expect to produce?

Question

Roberto Hays

Chemistry

5 June, 01:51

If you weighed out 0.38 g of calcium and reacted it with an excess of hcl, how many moles of h2 (g) would you expect to produce?

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Answers (1)

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Roderick Bonilla · Answer 1

Answer is: 0,0095 mol of hydrogen gas will be produced in reaction.

Chemical reaction: Ca + 2HCl → CaCl₂ + H₂.

m (Ca) = 0,38 g.

n (H₂) = ?

n (Ca) = m (Ca) : M (Ca).

n (Ca) = 0,38 g : 40 g/mol

n (Ca) = 0,0095 mol.

from reaction: n (Ca) : n (H₂) = 1 : 1.

n (H₂) = n (Ca) = 0,0095 mol.

n - amount of substance.