Consider the compound pb (so4) 2 and answer the following questions

A. what is the name of this compound?

Lead (IV) Sulfate

B. What is the molar mass if this compound? Explain how you calculated this value

Name of compound:Lead (IV) Sulfate

Molar mass:399 gmol-1

Explanation:

Note the relative atomic masses of the elements involved

Pb = 207, S=32, O=16

Hence Pb (SO4) 2 = 207 + 2[ 32+4 (16) ] = 207 + 192=399 gmol-1

The sum of the atomic masses of each atom present in a compound gives the molar mass (mass of one mole) of the compound as shown above.

Pb (SO₄) ₂:

A. The answer is Lead (IV) Sulfate.

That is the name of Pb (SO₄) ₂ is Lead (IV) Sulfate.

B.

mass of lead = 207.2 g

mass of sulfur = 2 * 32.065 g = 64.13 g

mass of oxygen = 8 * 16 = 128 g

total mass of Pb (SO₄) ₂ = (207.2 + 64.13 + 128)

= 399.33 g

molar mass of Pb (SO₄) ₂=399.33 g/mol