What is the pH of a 5.41g of HNO3 in 7L of solution? (mass of HNO3=63.02g)

1.9

Explanation:

Let us call to mind the formula

m/M = CV

Where

m = mass of the solute = 5.41 g

M = molar mass of the solute = 63.02g

C = concentration of the solution (the unknown)

V = volume of the solution = 7L

5.41 / 63.02g = 7C

0.0858 = 7C

C = 0.0858/7

C = 0.01226 molL-1

[H^+] = [HNO3] = 0.01226 molL-1

pH = - log [H^+]

pH = - log (0.01226)

pH = 1.9