Express the equilibrium constant for the combustion of ethanol in the balanced chemical equation. C2H5OH (g) + 3O2 (g) ⇌2CO2 (g) + 3H2O (g) Express the equilibrium constant for the combustion of ethanol in the balanced chemical equation. A) K=[C2H5OH][O2][CO2][H2O] B) K=[CO2]2[C2H5OH][O2]3 C) K=[CO2]2[H2O]3[C2H5OH][O2]3 D) K=[CO2][H2O][C2H5OH][O2]

Question

Zavier Schmitt

Chemistry

14 April, 07:30

Express the equilibrium constant for the combustion of ethanol in the balanced chemical equation. C2H5OH (g) + 3O2 (g) ⇌2CO2 (g) + 3H2O (g) Express the equilibrium constant for the combustion of ethanol in the balanced chemical equation. A) K=[C2H5OH][O2][CO2][H2O] B) K=[CO2]2[C2H5OH][O2]3 C) K=[CO2]2[H2O]3[C2H5OH][O2]3 D) K=[CO2][H2O][C2H5OH][O2]

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Answers (1)

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Layla Romero · Answer 1

The correct answer is C where K=[CO2]^2[H2O]^3/[C2H5OH][O2]^3

Explanation:

Equilibrium constant (K) is expressed as the product of all the products divided by the product of all reactants. the coefficient in front of each reactants or products are used as their exponents. Solids and liquids are considered to be 1 hence they are not shown, but in this case everything is in gaseous form thus they are all expressed in the equilibrium formula formula.