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23 May, 00:30

An aqueous solution in a 55 gallon (208 l drum), characterized by minimal buffering capacity, received 4kg of phenol and 1.5 kg of sodium phenate. What is the ph of the solution. The pka of phenol = 9.98. Mw of phenol and sodium phenate are 94 g/mol and 116 g/mol, respectively.

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  1. 23 May, 00:44
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    An aqueous solution in a 55 gallon (208 l drum), characterized by minimal buffering capacity, received 4kg of phenol and 1.5 kg of sodium phenate. What is the ph of the solution. The pka of phenol = 9.98. Mw of phenol and sodium phenate are 94 g/mol and 116 g/mol, respectively.

    Volume of solution = 55 gallons = 208.2 L [ 1 gallon = 3.78 L]

    moles of phenol = mass / molar mass = 4000 g / 94 = 42.55 moles

    moles of sodium phenate = mass / molar mass = 1500 / 116 = 12.93 moles

    pKa of phenol = 9.98

    We know that the pH of buffer is calculated using Hendersen Hassalbalch's equation

    pH = pKa + log [salt] / [acid]

    volume is same for both the sodium phenate and phenol has we can directly take the moles of each in the formula

    pH = 9.98 + log [12.93 / 42.55] = 9.46
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