The reaction 2HGOS (S) - 2Hg (1) + 02 (g), you produce 1 mole of HG. What is your percent yield? you expected to produce 2mol of HG.

100%

50%

30%

20%

Option 2. 50 %

Explanation:

Reaction: 2HgO (s) → 2Hg (l) + O₂ (g)

Ratio is 2:2, 2 moles of mercury oxide produce 2 moles of liquid mercury.

If you produced 1 mol of Hg, then the percent yield reaction is 50%

Percent yield is:

[Produced yield (what you produced) / Theoretical yield (what you excpected to be produced) ]. 100 → (1 mol of Hg / 2 mol of Hg).100 = 50%