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11 May, 17:27

Sodium hydroxide is available commercially as a 50.0% by weight aqueous solution. The density of the solution is 1.53 g/mL. Calculate the molarity of this sodium hydroxide solution. Sodium hydroxide is available commercially as a 50.0% by weight aqueous solution. The density of the solution is 1.53 g/mL. Calculate the molarity of this sodium hydroxide solution. 0.450 M 25.0 M 125. M 19.1 M

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  1. 11 May, 17:57
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    [NaOH] = 19.1 M

    Last option.

    Explanation:

    Sodium hydroxide is available commercially as a 50.0% by weight aqueous solution.

    50% by weight means, that in 100 g of solution we have 50 grams of solute.

    Molar mass of solute: 40 g/m

    Mass / Molar mass = moles

    50 g / 40 g/m = 1.25 moles

    These are the moles of solute in 100 grams of solution, so we must use density data, so we can find out our volume.

    Solution density = Solution mass / Solution volume

    1.53 g/mL = 100 g / Solution volume

    Solution volume = 100 g / 1.53 g/mL

    Solution volume = 65.3 mL

    1.25 moles of solute are in 65.3 mL of solution

    Molarity = moles / L

    Let's convert 65.3 mL in L

    65.3 / 1000 = 0.0653 L

    1.25 moles / 0.0653 L = 19.1 M
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