How much heat is released when 0.762 mol of copper cools from 81.6°C to 52.2°C?

550 J

Explanation:

The formula for the amount of heat (q) released by the copper is

q = mCΔT

dа ta:

n = 0.762 mol

C = 0.386 J°C⁻¹g⁻¹

T_i = 81.6 °C

T_f = 52.2 °C

Calculations:

(a) Mass of copper

/text{Mass} = / text{0.762 mol} / times / dfrac{/text{63.55 g}}{/text{1 mol}} = / text{48.43 g}

(b) ΔT

ΔT = 81.6 °C - 52.2 °C = 29.4 °C

(c) q

q = mCΔT = 48.43 g * 0.386 J·°C⁻¹g⁻¹ * 29.4 °C = 550 J

The amount of heat released by the copper is 550 J.