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27 November, 07:50

a 280.0 mL sample of neon exerts a pressure of 660.0 toff at 26.0 celsius. at what temperture would it exert a pressure of 940.0 torr in a volume of 0.44 L

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  1. 27 November, 08:07
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    T₂ = 669.2 K

    Explanation:

    Given dа ta:

    Initial pressure = 660 torr

    Initial temperature = 26 °C (26 + 273 = 299 K)

    Final volume = 280 mL (280/1000 = 0.28 L)

    Final pressure = 940.0 torr

    Final volume = 0.44 L

    Final temperature = ?

    Formula:

    P₁V₁/T₁ = P₂V₂/T₂

    P₁ = Initial pressure

    V₁ = Initial volume

    T₁ = Initial temperature

    P₂ = Final pressure

    V₂ = Final volume

    T₂ = Final temperature

    Solution:

    P₁V₁/T₁ = P₂V₂/T₂

    T₂ = P₂V₂ T₁ / P₁V₁

    T₂ = 940 torr * 0.44 L * 299 K / 660 torr * 0.28 L

    T₂ = 123666. 4 torr. L. K / 184.8 torr. L

    T₂ = 669.2 K
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