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22 August, 04:42

What mass of H2 gas (in

g. would be produced by the complete reaction of the aluminum block?

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Answers (1)
  1. 22 August, 05:07
    0
    First lets calculate the moles of aluminum (molar mass is 27 gram/mol):

    n = m/M = 14.9 / 27 = 0.551 mole of Al

    According to the reaction between sulfuric acid and aluminum:

    From 2 moles of aluminum = => we get 3 moles of Hydrogen gas

    so, let's do cross multiplication

    0.551 = => 0.551 * 3/2 = 0.83 mole of H2

    So, from this reaction we got 0.83 mole of H2 gas

    knowing that the molar mass of H2 is 2 gram/mol, the mass of the gas is.

    m = n * M = 0.83 * 2 = 1.66 gram of H2
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