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28 November, 20:23

How many molecules of sulfur trioxide are in 78.0 grams?

(A) 7.33 x 10^23

(B) 5.87 x 10^23

(C) 3.76 x 10^27

(D) 0.974

(E) none of the above

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  1. 28 November, 20:32
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    b) 5.87 E23 molecules

    Explanation:

    ∴ mm SO3 = 80.066 g/mol

    ⇒ molecules SO3 = (78.0 g) (mol/80.066 g) (6.022 E23 molec/mol)

    ⇒ molec SO3 = 5.866 E23 molecules SO3
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