How many molecules of sulfur trioxide are in 78.0 grams?

(A) 7.33 x 10^23

(B) 5.87 x 10^23

(C) 3.76 x 10^27

(D) 0.974

(E) none of the above

Question

Blossom

Chemistry

28 November, 20:23

How many molecules of sulfur trioxide are in 78.0 grams?

(A) 7.33 x 10^23

(B) 5.87 x 10^23

(C) 3.76 x 10^27

(D) 0.974

(E) none of the above

+2

Answers (1)

Know the Answer?

Matthias Bowen · Answer 1

b) 5.87 E23 molecules

Explanation:

∴ mm SO3 = 80.066 g/mol

⇒ molecules SO3 = (78.0 g) (mol/80.066 g) (6.022 E23 molec/mol)

⇒ molec SO3 = 5.866 E23 molecules SO3

How many molecules of sulfur trioxide are in 78.0 grams?(A) 7.33 x 10^23(B) 5.87 x 10^23(C) 3.76 x 10^27(D) 0.974(E) none of the above

How many molecules of sulfur trioxide are in 78.0 grams?

(A) 7.33 x 10^23

(B) 5.87 x 10^23

(C) 3.76 x 10^27

(D) 0.974

(E) none of the above