What mass of carbon dioxide forms when 95.6 g of propane burns?

First, you need to write and balance the reaction equation.

propane C3H8

C3H8 + 5O2 - - - > 3CO2 + 4H2O

the use stoichiometry and molar mass to solve

molar mass of propane = 44.1 g / mol

molar mass of CO2 = 44.0 g / mol

95.6 g C3H8 (1 mol / 44.1 grams) x (3 mol CO2 / 1 mol C3H8) x (44.0 grams / 1 mol CO2) = 286 grams CO2