Calculate the concentration (in mol/l) of 33% by weight (33 g naoh per 100 g of solution) naoh solution. (the density of the 33% by weight solution is 1.35 g/ml).

Question

Patience Garza

Chemistry

25 June, 02:09

Calculate the concentration (in mol/l) of 33% by weight (33 g naoh per 100 g of solution) naoh solution. (the density of the 33% by weight solution is 1.35 g/ml).

+5

Answers (1)

Know the Answer?

Jaxson Shaffer · Answer 1

Molarity is measured in moles per Liter. If there are 1.35 g/mL, find out how many grams there are in a liter of solution.

If there are 1000 mL in one liter, we can multiply by 1000 to get g/L

1.35 g/mL x 1 Liter/1000 mL = 1350 g per Liter of solution

By weight, the NaOH is 33% or. 33

1350 g x. 33 = 445.5 g of NaOH

Molar mass of NaOH is 39.997 g

445.5 g x 1 mol NaOH/39.997 g = 11.13833538 moles per Liter

Rounded to significant figures, the answer is 11 mol/L NaOH