Combining 0.380 mol Fe2O3 with excess carbon produced 13.7 g Fe

Fe2O3 + 3C → 2Fe + 3CO

What is the actual yield of iron in moles?

What is the theoretical yield of iron in moles?

What is the percent yield?

Percent yield = 32.9%

Explanation:

Given dа ta:

Number of moles of Fe₂O₃ = 0.380 mol

Number of moles of Fe produced = 13.7 g

Theoretical yield = ?

Actual yield of iron in mol = ?

Percent yield = ?

Solution:

Chemical equation:

Fe₂O₃ + 3C → 2Fe + 3CO

Actual yield of iron in moles:

Number of moles = mass / molar mass

Number of moles = 13.7 g / 55.8 g/mol

Number of moles = 0.25 mol

Theoretical yield:

Fe₂O₃ : Fe

1 : 2

0.380 : 2*0.380 = 0.76

Theoretical yield = 0.76 mol

Percent yield:

Percent yield = actual yield / theoretical yield * 100

Percent yield = 0.25 mol / 0.76 mol * 100

Percent yield = 32.9%