When excess solid mg (oh) 2 is shaken with 1.00 l of 1.3 m nh4cl solution, the resulting saturated solution has ph=9.10?

Question

Choi

Chemistry

24 January, 08:53

When excess solid mg (oh) 2 is shaken with 1.00 l of 1.3 m nh4cl solution, the resulting saturated solution has ph=9.10?

+3

Answers (1)

Know the Answer?

Stephen Evans · Answer 1

Missing question: calculate concentration of OH⁻ ion.

Chemical reaction: Mg (OH) ₂ + 2NH₄Cl → MgCl₂ + 2NH₄OH.

pH = 9.10.

[H+] = 10∧ (-pH).

[H+] = 10∧ (-9.10).

[H+] = 7.94·10⁻¹⁰ M.

[H+] · [OH⁻] = 10⁻¹⁴ M².

[OH⁻] = 10⁻¹⁴ M² : 7.94·10⁻¹⁰ M.

[OH⁻] = 1.25·10⁻⁵ M.