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18 October, 12:48

How many moles of oxygen are required to produce 436 L of water vapor?

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  1. 18 October, 13:14
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    The reaction for formation of water vapour is as follows;

    2H2 + O2 - > 2H2O

    Water vapour is in the gaseous form, at STP, 1 mol of any gas occupies 22.4 L volume

    If 22.4 L occupied by 1 mol

    Then amount of moles in 436 L - 1/22.4 x 436 = 19.5 mol

    Stoichiometry of O2 to H2O is 1:2

    Amount of O2 moles reacted to formed H2O is - 19.5 mol / 2 = 9.75 mol
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