What is the pressure of 0.5 mol nitrogen (N.) gas in a 5.0 L container at 203

(The universal gas constant is 0.0821 L'atm/mol K.)

O

A. 170 atm

O

B. 1.7 atm

O

C. 42 atm

O

0.60 atm

B) P = 1.7 atm

Explanation:

Number of moles of nitrogen = 0.5 mol

Volume = 5.0 L

Temperature = 203 K

Pressure = ?

Solution:

PV = nRT

P = nRT/V

P = 0.35 mol * 0.0821 atm. L. mol⁻¹. K⁻¹ * 203 K / 5.0 L

P = 8.333 atm / 5.0

P = 1.7 atm