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7 March, 12:13

Suppose that 2.5 mmol n2 (g) occupies 42 cm3 at 300 k and expands isothermally to 600 cm3. calculate Î'gm in kj/mol for the process. hint: boyle's law p1v1=p2v2

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  1. 7 March, 12:22
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    Given:

    MilliMoles of N2 = 2.5 mmol = 0.0025 moles

    Initial volume V1 = 42 cm3

    Final volume V2 = 600 cm3

    Temperature T = 300 K

    To determine:

    The change in Gibbs free energy, ΔG

    Explanation:

    The change in Gibbs free energy is related to the ration of the volumes:

    ΔG = - nRTln (V2) / (V1)

    = - 0.0025*8.314*300*ln (600/42) = - 16.582 J/mol

    Ans: The Gibbs free energy for the process is 0.0166 kJ/mol
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