A sample of aluminum metal absorbs 8.32 J of heat, upon which the temperature of the sample increases from 23.2 degrees C to 30.5 degrees C. Since the specific heat capacity of aluminum is 0.90 J/g-K, the mass of the sample is what in grams?

Question

Brody Lam

Chemistry

11 September, 03:17

A sample of aluminum metal absorbs 8.32 J of heat, upon which the temperature of the sample increases from 23.2 degrees C to 30.5 degrees C. Since the specific heat capacity of aluminum is 0.90 J/g-K, the mass of the sample is what in grams?

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Answers (1)

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Ean Daugherty · Answer 1

Given:

8.32 J of heat

from 23.2 degrees C to 30.5 degrees C

heat capacity of aluminum is 0.90 J/g-K

Required:

m in grams

Solution:

H = mCpT

(8.32 J) = m (0.90 J/g-K) (30.5 - 23.2) K

m = 1.27g