Radical chlorination of pentane is a poor way to prepare 1-chloropentane, but radical chlorination of neopentane, (CH3) 4C, is a good way to prepare neopentyl chloride, (CH3) 3CCH2Cl.

Why? ... ?

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Chemistry

16 October, 08:15

Radical chlorination of pentane is a poor way to prepare 1-chloropentane, but radical chlorination of neopentane, (CH3) 4C, is a good way to prepare neopentyl chloride, (CH3) 3CCH2Cl.

Why? ... ?

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Selah · Answer 1

Because it’s random that CH3CH2CH2CH2CH3 losing a (·H), so by reaction with Cl2, it can form many isomers, such as CH3CH2CH2CHClCH3, CH3CH2CHClCH2CH3, CH3CH2CH2CH2CH2Cl, so a poor way to prepare 1-chloropentane. While for (CH3) 4C, each of the H atom are equivalent. So no matter which one be substituted, only one product, (CH3) CCH2Cl, can be prepared.

Radical chlorination of pentane is a poor way to prepare 1-chloropentane, but radical chlorination of neopentane, (CH3) 4C, is a good way to prepare neopentyl chloride, (CH3) 3CCH2Cl.Why? ... ?

Radical chlorination of pentane is a poor way to prepare 1-chloropentane, but radical chlorination of neopentane, (CH3) 4C, is a good way to prepare neopentyl chloride, (CH3) 3CCH2Cl.

Why? ... ?