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31 May, 07:00

What is the value of work done on an object when a 50-newton force moves it 15 meters in the same direction as the force?

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  1. 31 May, 07:10
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    The answer is 7.5 * 10² J

    A work (W) is a product of a force (F) and a distance (d):

    W = F · d

    It is known:

    F = 50 N

    d = 15 m

    W = ?

    So, let's just substitute the parameters:

    W = 50 N * 15 m = 750 N*m = 750 J = 7.5 * 10 ² J
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