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24 November, 20:44

How many neon atoms are contained in (7.27x10^2) grams of neon?

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  1. 24 November, 20:54
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    Answer: 2.19x10^25 atoms

    Explanation:

    Molar Mass of Neon = 20g/mol

    1mole (20g) of Neon contains 6.02x10^23 atoms.

    Therefore, 7.27x10^2g of Neon will contain x atoms i. e

    X atoms = (7.27x10^2x6.02x10^23) / 20 = 2.19x10^25 atoms
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