How many sulfur atoms would be present in 41.8 miles of sulfur

Answer: 2.51 x 10*25 atoms

Explanation:

Recall that based on Avogadro's number,

1 mole of any substance has 6.02 x 10*23 atoms

So if 1 mole of sulphur = 6.02 x 10*23 atoms

41.8 moles of sulfur = Z

To get the value of Z, we cross multiply:

1 mole x Z atoms = 41.8 moles x 6.02 x 10*23 atoms

Z = 251.636 x 10*23

Place the result in standard form

Hence, Z = 2.51 x 10*25 atoms

Thus, the number of sulfur atoms present in 41.8 miles of sulfur is 2.51 x 10*25 atoms