What is the molality of a solution in which 55g of sucrose are dissolved in 950mL of water?

0.169M

Explanation:

The following were obtained from the question:

Mass of sucrose (C12H22O11) = 55g

Volume of solution = 950 mL

Next, we shall determine the number of mole of sucrose in 55g of sucrose. This is illustrated below:

Mass of C12H22O11 = 55g

Molar Mass of C12H22O11 = (12x12) + (22x1) + (16x11) = 144 + 22 + 176 = 342g/mol

Number of mole = Mass/Molar Mass

Number of mole C12H22O11 = 55/342 = 0.161 mole

Next, we shall convert 950 mL to L. This is illustrated below:

1000mL = 1L

Therefore, 950mL = 950/1000 = 0.95L

Now, we can calculate the molarity of the solution as follow:

Molarity = mole / Volume

Mole of C12H22O11 = 0.161 mole

Volume = 0.95L

Molarity = 0.161 / 0.95

Molarity = 0.169M