500. mL of gas is contained at STP. The volume changes to 560 mL at 20.°C

What is the pressure (in atm) ?

P₂ = 0.96 atm

Explanation:

Given dа ta:

Initial volume = 500 mL

Initial pressure = 1 atm

Initial temperature = 273 K

Final volume = 560 mL

Final temperature = 20°C (20 + 273 = 293K)

Final pressure = ?

Formula:

P₁V₁/T₁ = P₂V₂/T₂

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

According to general gas equation:

P₁V₁/T₁ = P₂V₂/T₂

P₂ = P₁V₁ T₂ / T₁ V₂

P₂ = 1 atm * 500 mL * 293 K / 273 K * 560 mL

P₂ = 146500 atm. mL. K / 152880 k. mL

P₂ = 0.96 atm