1. Given the following balanced equation:

Mg + CuCl2 → MgCl2 + Cu

Calculate the amount of copper produced beginning with 100g of Mg and 200 g of CuCl2 and identify the limiting reactant.

94.7 g

The limiting reactant is CuCl2

Explanation:

The limiting reagent is the reagent with the least amount of moles. Converting grams to moles, you should find that there is 4.11 mol Mg and 1.49 mol CuCl2. CuCl2 is the limiting reagent.

The limiting reagent is what you will use to determine how much product you have. By stoichiometry, you can see that for every mole of CuCl2, you have one mole of Cu. So, that means we have 1.49 mol Cu. Convert to grams. Your answer should be 94.7 g.