What is the pOH of a 0.00037 M solution of barium hydroxide

Answer: pOH = 3.13

Ba (OH) 2 is a very basic substance. The general formula for pOH is - log (OH)

Barium Hydroxide produces 2 moles of OH for every mole of Ba (OH) 2 present in the solution.

0.00037 M = 3.7 * 10^-4 Ba (OH) 2 will produce 2 * 0.00037 M of OH-

OH - = 2 * 0.00037 = 0.00074

pOH = - log (0.00074) = 3.13