Since this reaction takes place in acidic solution, H2O (l) and H + (aq) will be involved in the reaction. Places for these species are indicated by the blanks in the following restatement of the equation: SO42 - (aq) + Sn2 + (aq) + - --→H2SO3 (aq) + Sn4 + (aq) + - - - Part A What are the coefficients of the reactants and products in the balanced equation above? Remember to include H2O (l) and H + (aq) in the appropriate blanks. Your answer should have six terms.

The balanced equation is given below:

SO4^2 - (aq) + Sn^2 + (aq) + 4H^ + (aq) → H2SO3 (aq) + Sn^4 + (aq) + H2O (l)

The coefficients of the reactants are: 1, 1, 4

The coefficients of the products are: 1, 1, 1

Explanation:

Step 1:

The equation for the reaction. This is given below:

SO4^2 - (aq) + Sn^2 + (aq) + - --→ H2SO3 (aq) + Sn^4 + (aq) + - --

Step 2:

Inclusion of H + and H2O into the equation. This is illustrated below:

SO4^2 - (aq) + Sn^2 + (aq) + H^ + (aq) → H2SO3 (aq) + Sn^4 + (aq) + H2O (l)

Step 3:

Balancing the equation.

SO4^2 - (aq) + Sn^2 + (aq) + H^ + (aq) → H2SO3 (aq) + Sn^4 + (aq) + H2O (l)

The above equation can be balanced as follow:

There are total 4 atoms of H on the right side and 1 atom on the left side. It can be balance by putting 4 in front of H^ + as shown below:

SO4^2 - (aq) + Sn^2 + (aq) + 4H^ + (aq) → H2SO3 (aq) + Sn^4 + (aq) + H2O (l)

Now the equation is balanced.

The coefficients of the reactants are: 1, 1, 4

The coefficients of the products are: 1, 1, 1