What mass (g) of potassium chloride is contained in 430.0 mL of a potassium chloride solution that has a chloride ion concentration of 0.193 M?

6.178 g.

Explanation:

KCl is ionized in the solution as:

KCl → K⁺ + Cl⁻.

∴ [KCl] = [K⁺] = [Cl⁻] = 0.193 M.

Molarity is defined as the no. of moles of the solute per 1.0 L of the solution.

∵ M = [ (mass/molar mass) KCl][ (1000) / (V of the solution) ].

∴ mass of KCl = (M) (molar mass of KCl) (V of the solution) / 1000 = (0.193 M) (74.55 g/mol) (430.0 mL) / 1000 = 6.178 g.