Assume that the enthalpy of fusion of ice is 6020 J/mol and does not vary appreciably over the temperature range 270-290 K. If 1.40 mol of ice at 0°C is melted by heat supplied from surroundings at 284 K, what is the entropy change in the surroundings in J/K

29.7 J/K

Explanation:

To solve this problem we can use the equation

ΔS = Δq/T

Where ΔS is the entropy change, Δq is the heat change, and T is the temperature.

Δq = ΔH*mol

We put the data given by the problem and solve for ΔS:

ΔS = 6020J/mol * 1.40 mol / 284 K ΔS = 29.7 J/K