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30 April, 09:51

What is an empirical formula for a compound that is 82.2% nitrogen and 17.8% hydrogen

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  1. 30 April, 10:15
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    Percent to mass

    Mass to mole

    Divide by small

    Multiply 'til whole

    Assume 100 g of substance, then 82.2 g N and 17.8 g H.

    82.2 g N * (1 mol/14.01 g N) = 5.86 mol N

    17.8 g H * (1 mol/1.01 g H) = 17.6 mol H

    Divide by the smallest mole

    17.6 H / 17.6 = 1 H

    5.86 N / 17.6 = 1/3 N

    Multiply to make whole number (x3 in this case)

    3 x 1 H = 3H

    3 x 1/3 N = 1 N

    NH3
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