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12 January, 23:58

What is the molality of 151 grams of na2so4 dissolved in 547 g of water?

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  1. 13 January, 00:20
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    Molar mass Na2SO4 = > 142.04 g/mol

    Number of moles:

    n = sample mass / molar mass

    n = 151 / 142.04 = > 1.063 moles

    Mass of solvent in kilograms:

    1 kg = 1000 g

    574 g / 1000 = 0.574 kg

    Therefore:

    b = n solute / m solvent

    b = 1.063 / 0.547

    b = 1.943 mol/kg
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