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6 November, 08:33

What is the temperature of 1.2 moles of helium gas at 2.57 ATM if it occupies 15.5L of volume

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  1. 6 November, 08:36
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    We will assume helium to behave as an ideal gas and apply the ideal gas law:

    PV = nRT

    For pressure measured in atmospheres and volume measured in liters, the value of the molar gas constant is 0.082. Therefore:

    T = PV / nR

    T = (2.57 x 15.5) / (1.2 x 0.082)

    T = 404.8 Kelvin
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