How many grams of potassium iodine, kl, must be added to 500.0 grams of water to produce a 6.00% solution?

grams KI needed = 31.9 grams

Explanation:

? g KI + 500 g water = > 6.0% KI solution

let x = grams KI needed.

Percent = part/total x 100% = (x/x+500) ·100% = 6.0%

Solve for 'x' ...

x / x + 500 = 6/100 = 0.06 = > x = 0.06 (x + 500) = > x = 0.06x + 30

x - 0.06x = 30 = > 0.94x = 30 = > x = 30/0.94 = 31.9 gms KI needed.