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22 November, 22:39

A pure titanium cube has an edge length of 2.66 in. how many titanium atoms does it contain? titanium has a density of 4.50 g/cm3.

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Answers (2)
  1. 22 November, 22:41
    0
    Volume of Cube = edge length^3

    V=2.66*2.66*2.66

    V=18.82 in^3

    because density is in cm^3

    so converting V from in^3 to cm^3

    V=314.12 cm^3

    mass=density * volume

    mass = 4.5*314.12

    mass=1413.54 g

    The molar mass of titanium is 47.88 g/mole

    so moles=1413.54/47.88

    moles=29.52

    now one mole has avogadro number of atoms

    so number of atoms=29.52*avogadro number

    number of atoms=1.77x10^25
  2. 22 November, 22:45
    0
    The volume of the cube will be 2.66 * 2.66 * 2.66 = 18.821 cubic inches.

    1 cubic inch = 16.387 cubic centimeter.

    18.821 cubic inches will be 18.821 * 16.387 = 308.42 cubic centimeter.

    Density is 4.5 g/cm³

    Therefore, mass will be 308.42 * 4.5 = 1387.89 g

    1 mole of Titanium = 47.877 g, so the number of moles will be 1387.89/47.877=28.99 moles.

    1 mole = 6.02 * 10^23 atoms

    Therefore, 28.99 moles * 6.02 * 10^23 atoms = 1.745 * 10^25 atoms.
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