How many liters are in 3.36 grams of F2 gas at STP

Volume = 3.98L

Explanation:

Volume = ?

Mass = 3.36g

Pressure at STP = 1atm

Temperature at STP = 273.15k

Molarmass = 18.99g/mol

R = 0.082J/mol. K

From ideal gas equation

PV = nRT

P = pressure

V = volume the gas occupies

n = number of moles,

R = ideal gas constant

T = temperature of the gas

PV = nRT

Number of moles = mass / molarmass

n = 3.36 / 18.99

n = 0.1769 moles

PV = nRT

Solve for V

V = nRT / P

V = (0.1769 * 0.082 * 273.15) / 1

V = 3.96L

The volume the gas occupies is 3.96L