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11 December, 04:53

What is an important step to determine the number of grams of SO3 that can be produced by reacting 6 moles of SO2 with oxygen in the synthesis reaction below. 2 SO2 (g) + O2 (g) - >2 SO3 (g)

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  1. 11 December, 05:21
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    480.40 g.

    Explanation:

    According to the balanced equation:

    2 SO₂ (g) + O₂ (g) → 2 SO₃ (g),

    it is clear that 2.0 moles of SO₂ react with 1.0 mole of oxygen to produce 2.0 moles of SO₃.

    We can get the no. of moles of SO₃ produced:

    ∵ 2.0 moles of SO₂ produce → 2.0 moles of SO₃, from the stichiometry.

    ∴ 6.0 moles of SO₂ produce → 6.0 moles of SO₃.

    Then, we can get the mass of the produced 6.0 moles of SO₃ using the relation:

    mass = no. of moles x molar mass of SO₃ = (6.0 moles) (80.066 g/mol) = 480.396 g ≅ 480.40 g.
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