Consider the reaction: so2cl2 (g) ⇌so2 (g) + cl2 (g) kp=2.91*103 at 298 k in a reaction at equilibrium, the partial pressure of so2 is 0.156 atm and that of cl2 is 0.370 atm. part a what is the partial pressure of so2cl2 in this mixture?

Question

Iyana Quinn

Chemistry

5 July, 13:50

Consider the reaction: so2cl2 (g) ⇌so2 (g) + cl2 (g) kp=2.91*103 at 298 k in a reaction at equilibrium, the partial pressure of so2 is 0.156 atm and that of cl2 is 0.370 atm. part a what is the partial pressure of so2cl2 in this mixture?

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Adrienne · Answer 1

1.98 x 10⁻⁵ atm.

Explanation:

For the reaction: SO₂Cl₂ (g) ⇌ SO₂ (g) + Cl₂ (g), Kp = 2.91 x 10³.

∵ Kp = (PSO₂) (PCl₂) / (PSO₂Cl₂).

PSO₂ = 0.156 atm, PCl₂ = 0.370 atm.

∴ 2.91 x 10³ = (0.156 atm) (0.370 atm) / (PSO₂Cl₂)

∴ (PSO₂Cl₂) = (0.156 atm) (0.370 atm) / (2.91 x 10³) = 1.98 x 10⁻⁵ atm.