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20 November, 04:43

2.5 piece of lithium is dropped into a 500 g sample of water at 22.1 C. ten temperature of the water increases to 23.5 C. How much heat energy is released in the reaction

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  1. 20 November, 04:58
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    2.6 kJ

    Explanation:

    The formula for the amount of heat (q) absorbed by the water is

    q = mCΔT

    1. Calculate ΔT

    ΔT = 23.5 °C - 22.1 °C = 1.4 °C

    2. Calculate q

    q₂ = mCΔT = 500 g * 4.184 J·°C⁻¹g⁻¹ * 1.4 °C = 2900 J = 2.9 kJ
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