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3 July, 16:16

Assuming that the smallest measurable wavelength in an experiment is 0.730 fm (femtometers), what is the maximum mass of an object traveling at 927 m·s-1 for which the de Broglie wavelength is observable?

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  1. 3 July, 16:43
    0
    1 fm = 1.0 * 10-15 meters

    so

    0.610 fm x (1.0x10^-15 m / 1 fm)

    = 6.1x10^-16 m

    so the formula is

    λ = h / mu

    so,

    as we know mass value so by putting

    m = (6.626*10^-34) / (6.1*10^-16*199)

    = (6.626*10^-34) / (1213.96 * 10^-16)

    = 5.45 x 10^ - 21

    hope thats an answer for you
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