Ask Question
24 March, 03:16

For the reaction 8 H 2 S (g) - ⇀ ↽ - 8 H 2 (g) + S8 (g) 8H2S (g) ↽--⇀8H2 (g) + S8 (g) the equilibrium concentrations were found to be [ H 2 S ] = 0.250 M, [H2S]=0.250 M, [ H 2 ] = 0.600 M, [H2]=0.600 M, and [ S 8 ] = 0.750 M. [S8]=0.750 M. What is the equilibrium constant for this reaction

+2
Answers (1)
  1. 24 March, 03:37
    0
    Kc = 826

    Explanation:

    For the equilibrium:

    8 H₂S (g) ⇄ 8 H₂ (g) + S₈ (g)

    the equilibrium constant is:

    Kc = [ H₂ ] ⁸ x [ S₈ ] / [H₂S]⁸

    Kc = 0.600⁸ x 0.750 / (0.250) ⁸ = 1.68 x 10⁻² x 0.750 / 1.53 x 10⁻⁵

    = 824

    Be careful with raising to the power of 8 in your calculator.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “For the reaction 8 H 2 S (g) - ⇀ ↽ - 8 H 2 (g) + S8 (g) 8H2S (g) ↽--⇀8H2 (g) + S8 (g) the equilibrium concentrations were found to be [ H 2 ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers