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14 April, 13:08

What means of NO2 is contained in a 13.0L tank at 464 kpa and 112 Celsius 289g 191 g 86.5 g 1.88 g

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  1. 14 April, 13:34
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    = 86.5 g

    Explanation:

    Using the equation;

    PV = n RT

    where P is the pressure, 464 kpa or 4.58 atm

    V is the volume, 13.0 l

    n is the number of moles

    R is the ideal gas constant, 0.0821 atm L/mol/K

    T is the temperature, 112 + 273.15 = 385.15 K

    Therefore;

    n = PV/RT

    n = (4.58 * 13) / (0.0821*385.15)

    = 1.883 moles

    The mass will be;

    = 1.883 moles * 46.0 g/mol

    = 86.57 g

    = 86.5 g
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