How many molecules of liquid ethanol (CH3H2OH) are in 1.00 mL of ethanol, given its density is 0.789 g/mL?

Question

Kamari York

Chemistry

19 July, 02:22

How many molecules of liquid ethanol (CH3H2OH) are in 1.00 mL of ethanol, given its density is 0.789 g/mL?

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Annalise · Answer 1

To get the molecules contained in liquid ethanol, we multiply the density to the given volume, that is equal to 0.789 g ethanol. In this case, we divide by molar mass and multiply by the constant, Avogadro's number. The answer is 1.033 x 10^22 molecules.