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3 July, 15:52

Convert the given amount as noted.

1.51 times 10^24 formula units of Iron (II) hydroxide to grams

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Answers (1)
  1. 3 July, 15:58
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    Answer: 225.75g

    Explanation:

    Molar Mass of Fe (OH) 2 = 56 + 2 (16 + 1) = 56 + 2 (17) = 56 + 34 = 90g/mol

    1mole (90g) of Fe (OH) 2 contained 6.02x10^23 units.

    Therefore, Xg of Fe (OH) 2 will contain 1.51x10^24 units

    Xg of Fe (OH) 2 = (90x1.51x10^24) / 6.02x10^23 = 225.75g
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