Convert the given amount as noted.

1.51 times 10^24 formula units of Iron (II) hydroxide to grams

Question

Damian Bauer

Chemistry

3 July, 15:52

Convert the given amount as noted.

1.51 times 10^24 formula units of Iron (II) hydroxide to grams

+3

Answers (1)

Know the Answer?

Lindsay Chambers · Answer 1

Answer: 225.75g

Explanation:

Molar Mass of Fe (OH) 2 = 56 + 2 (16 + 1) = 56 + 2 (17) = 56 + 34 = 90g/mol

1mole (90g) of Fe (OH) 2 contained 6.02x10^23 units.

Therefore, Xg of Fe (OH) 2 will contain 1.51x10^24 units

Xg of Fe (OH) 2 = (90x1.51x10^24) / 6.02x10^23 = 225.75g

Convert the given amount as noted.1.51 times 10^24 formula units of Iron (II) hydroxide to grams

Convert the given amount as noted.

1.51 times 10^24 formula units of Iron (II) hydroxide to grams