A driver blows 0.75 - L air bubble 10 m under water. As it rises to the surface, the pressure goes from 2.25 atm to 1.03 atm. What will be the volume of air in the bubble at the surface?

Question

Jane Neal

Chemistry

29 June, 11:12

A driver blows 0.75 - L air bubble 10 m under water. As it rises to the surface, the pressure goes from 2.25 atm to 1.03 atm. What will be the volume of air in the bubble at the surface?

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Answers (1)

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Wesley Frost · Answer 1

1.64 L

Explanation:

P₁V₁ = P₂V₂

P₁ = 2.25 atm

V₁ = 0.75 L

P₂ = 1.03 atm

V₂ = ?

(2.25 atm) (0.75 L) = (1.03 atm) V₂

[ (2.25 atm) (0.75 L) ] / (1.03 atm) = V₂

V₂ = 1.64 L