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2 February, 18:33

A balloon that had a volume of 3.50 L at 25.0°C is placed in a hot room at 40.0°C. If the pressure remains constant at 1.00 atm, what is the new volume of the balloon in the hot room?

Use StartFraction V subscript 1 over T subscript 1 EndFraction equals StartFraction V subscript 2 over T subscript 2 EndFraction ...

2.19 L

3.33 L

3.68 L

5.60 L

+2
Answers (2)
  1. 2 February, 18:46
    0
    3.68 L

    Explanation:

    use charle's law formula

    v1 (t2) = v2 (t1)

    and convert celsius to kelvin k=C+273.15

    3.5L (313.15K) = v2 (298.15K)

    solve for v2 by dividing 298.15k on both sides

    v2=3.68
  2. 2 February, 19:01
    0
    The answer is 3.68 L
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